What is the answer to 3x-4=sqrt(2x^2-3x+2) ?

The answer to 3x-4=sqrt(2x^2-3x+2) is x=2

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3x-4=sqrt(2x^2-3x+2)

3 x - 4 = 2 x^{2} - 3 x + 2

x = 2

Solution steps

3 x - 4 = 2 x^{2} - 3 x + 2

Square both sides:

9 x^{2} - 24 x + 16 = 2 x^{2} - 3 x + 2

9 x^{2} - 24 x + 16 = 2 x^{2} - 3 x + 2

Solve

9 x^{2} - 24 x + 16 = 2 x^{2} - 3 x + 2 : x = 2, x = 1

x = 2, x = 1

Verify Solutions:

x = 2

True

, x = 1

False

The solution is

x = 2

- 3 + 15 x + 10 = 7

x + x + 11 = 11

8 x + 4 + 10 = 16

7 + 2 (4 x^{2.6} - 3) = 33

8 x + 49 + 7 = x

What is the answer to 3x-4=sqrt(2x^2-3x+2) ?
The answer to 3x-4=sqrt(2x^2-3x+2) is x=2
Solve for x: 3x-4=sqrt(2x^2-3x+2)
The solution is x=2