What is the answer to sqrt(2x^2+3x-2)=0 ?

The answer to sqrt(2x^2+3x-2)=0 is x= 1/2 ,x=-2

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sqrt(2x^2+3x-2)=0

2 x^{2} + 3 x - 2 = 0

x = \frac{1}{2}, x = - 2

Decimal Notation

x = 0.5, x = - 2

Solution steps

2 x^{2} + 3 x - 2 = 0

Square both sides:

2 x^{2} + 3 x - 2 = 0

2 x^{2} + 3 x - 2 = 0

Solve

2 x^{2} + 3 x - 2 = 0 : x = \frac{1}{2}, x = - 2

x = \frac{1}{2}, x = - 2

Verify Solutions:

x = \frac{1}{2}

True

, x = - 2

True

The solutions are

x = \frac{1}{2}, x = - 2

\frac{1}{2} u = u

a (x) = - x + 3

x + x = 2 x - 12

35 + 7 x + 5 x + 34 = 3

15 - 2 r = r

What is the answer to sqrt(2x^2+3x-2)=0 ?
The answer to sqrt(2x^2+3x-2)=0 is x= 1/2 ,x=-2
Solve for x: sqrt(2x^2+3x-2)=0
The solution is x= 1/2 ,x=-2