What is the answer to sqrt(x^2+3x+6)-3x=x^2+4 ?

The answer to sqrt(x^2+3x+6)-3x=x^2+4 is x=-1,x=-2

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sqrt(x^2+3x+6)-3x=x^2+4

x^{2} + 3 x + 6 - 3 x = x^{2} + 4

x = - 1, x = - 2

Solution steps

x^{2} + 3 x + 6 - 3 x = x^{2} + 4

Remove square roots

x^{2} + 3 x + 6 = x^{4} + 6 x^{3} + 17 x^{2} + 24 x + 16

Solve

x^{2} + 3 x + 6 = x^{4} + 6 x^{3} + 17 x^{2} + 24 x + 16 : x = - 1, x = - 2

x = - 1, x = - 2

Verify Solutions:

x = - 1

True

, x = - 2

True

The solutions are

x = - 1, x = - 2

3.7 \cdot x^{\frac{1}{2}} - 2.2 = 0

10 y + 14 = 7 y + 1 + 2

2 = x - 4

y + 5 = 7

x^{\frac{4}{3}} = - 49

What is the answer to sqrt(x^2+3x+6)-3x=x^2+4 ?
The answer to sqrt(x^2+3x+6)-3x=x^2+4 is x=-1,x=-2
Solve for x: sqrt(x^2+3x+6)-3x=x^2+4
The solution is x=-1,x=-2