What is the answer to \sqrt[3]{x+1}=\sqrt[3]{x}+1 ?

The answer to \sqrt[3]{x+1}=\sqrt[3]{x}+1 is x=-1,x=0

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\sqrt[3]{x+1}=\sqrt[3]{x}+1

x = - 1, x = 0

Solution steps

Rewrite the equation with

and

x = u^{3} - 1

Solve

u = 0, u = 1

Substitute back

solve for

x

Solve

x = - 1, x = 0

Verify Solutions:

x = - 1

True

, x = 0

True

The solutions are

x = - 1, x = 0

4 n + 8 = n + 3

5 - 10 x = x + 7

x - 11 x - 60 = 0

x + 1 - 2 x + 11 = 0

2 x + \frac{2}{x} = 5

What is the answer to \sqrt[3]{x+1}=\sqrt[3]{x}+1 ?
The answer to \sqrt[3]{x+1}=\sqrt[3]{x}+1 is x=-1,x=0
Solve for x: \sqrt[3]{x+1}=\sqrt[3]{x}+1
The solution is x=-1,x=0