What is the answer to 2(x+1)=sqrt(2x^2+5x+6) ?

The answer to 2(x+1)=sqrt(2x^2+5x+6) is x= 1/2

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2(x+1)=sqrt(2x^2+5x+6)

2 (x + 1) = 2 x^{2} + 5 x + 6

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

2 (x + 1) = 2 x^{2} + 5 x + 6

Expand

2 (x + 1) : 2 x + 2

2 x + 2 = 2 x^{2} + 5 x + 6

Square both sides:

4 x^{2} + 8 x + 4 = 2 x^{2} + 5 x + 6

4 x^{2} + 8 x + 4 = 2 x^{2} + 5 x + 6

Solve

4 x^{2} + 8 x + 4 = 2 x^{2} + 5 x + 6 : x = \frac{1}{2}, x = - 2

x = \frac{1}{2}, x = - 2

Verify Solutions:

x = \frac{1}{2}

True

, x = - 2

False

The solution is

x = \frac{1}{2}

3 x + 63 - 3 = 6

x^{2} - x - 5 = x + 5

(12 h - 16)^{\frac{4}{3}} - 1 = 15

v^{\frac{1}{3}} = 4

- 2 x + 4 = - 12

What is the answer to 2(x+1)=sqrt(2x^2+5x+6) ?
The answer to 2(x+1)=sqrt(2x^2+5x+6) is x= 1/2
Solve for x: 2(x+1)=sqrt(2x^2+5x+6)
The solution is x= 1/2