What is the answer to sqrt(3x-3)+1=sqrt(3x+6) ?

The answer to sqrt(3x-3)+1=sqrt(3x+6) is x= 19/3

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sqrt(3x-3)+1=sqrt(3x+6)

3 x - 3 + 1 = 3 x + 6

x = \frac{19}{3}

Decimal Notation

x = 6.33333 \dots

Solution steps

3 x - 3 + 1 = 3 x + 6

Remove square roots

12 x - 12 = 64

Solve

12 x - 12 = 64 : x = \frac{19}{3}

x = \frac{19}{3}

Verify Solutions:

x = \frac{19}{3}

True

The solution is

x = \frac{19}{3}

x + 4 x + 25 = - 1

3 t + 7 = - 4

y^{\frac{1}{4}} = 2

(3 x + 1) + (x - 1) = 6

What is the answer to sqrt(3x-3)+1=sqrt(3x+6) ?
The answer to sqrt(3x-3)+1=sqrt(3x+6) is x= 19/3
Solve for x: sqrt(3x-3)+1=sqrt(3x+6)
The solution is x= 19/3