What is the answer to sqrt(2x^2)-1=x ?

The answer to sqrt(2x^2)-1=x is x=1-sqrt(2),x=1+sqrt(2)

Solve for x: sqrt(2x^2)-1=x

The solution is x=1-sqrt(2),x=1+sqrt(2)

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2 x^{2} - 1 = x

x = 1 - 2, x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 2.41421 \dots

Solution steps

2 x^{2} - 1 = x

Remove square roots

2 x^{2} = x^{2} + 2 x + 1

Solve

2 x^{2} = x^{2} + 2 x + 1 : x = 1 - 2, x = 1 + 2

x = 1 - 2, x = 1 + 2

Verify Solutions:

x = 1 - 2

True

, x = 1 + 2

True

The solutions are

x = 1 - 2, x = 1 + 2

a, a + 2 ab + b = 36

y, x = 2 5 y

6 x - 1 = 5

x + 6 + 2 x = 9

x^{2} - 7 = x - 1

What is the answer to sqrt(2x^2)-1=x ?
The answer to sqrt(2x^2)-1=x is x=1-sqrt(2),x=1+sqrt(2)
Solve for x: sqrt(2x^2)-1=x
The solution is x=1-sqrt(2),x=1+sqrt(2)