What is the answer to sqrt(x)+\sqrt[3]{x}+x=76 ?

The answer to sqrt(x)+\sqrt[3]{x}+x=76 is x=64

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sqrt(x)+\sqrt[3]{x}+x=76

x = 64

Solution steps

Use the following exponent property

Rewrite the equation with

u^{\frac{3}{2}} + u + u^{3} = 76

Solve

u^{\frac{3}{2}} + u + u^{3} = 76 : u = 4

u = 4

Substitute back

solve for

x

Solve

x = 64

Verify Solutions:

x = 64

True

The solution is

x = 64

x = 2 x 4 - x^{2}

x = 2 x - 1

- 4 = x

9 x^{\frac{1}{2}} = 3 x

What is the answer to sqrt(x)+\sqrt[3]{x}+x=76 ?
The answer to sqrt(x)+\sqrt[3]{x}+x=76 is x=64
Solve for x: sqrt(x)+\sqrt[3]{x}+x=76
The solution is x=64