What is the answer to \sqrt[3]{x^2+2x}=-1 ?

The answer to \sqrt[3]{x^2+2x}=-1 is x=-1

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\sqrt[3]{x^2+2x}=-1

x = - 1

Solution steps

Take both sides of the equation to the power of

3 : x^{2} + 2 x = - 1

x^{2} + 2 x = - 1

Solve

x^{2} + 2 x = - 1 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

140 = 356 d

6 + 2 x - 9 = x

3 (x + 1)^{\frac{3}{4}} = 24

4 x + 12 = x

x, y = x 16 - x^{2}

What is the answer to \sqrt[3]{x^2+2x}=-1 ?
The answer to \sqrt[3]{x^2+2x}=-1 is x=-1
Solve for x: \sqrt[3]{x^2+2x}=-1
The solution is x=-1