What is the answer to asqrt(x^2+d)+b=c ?

The answer to asqrt(x^2+d)+b=c is x=(sqrt(-da^2+c^2-2bc+b^2))/a ,x=-(sqrt(-da^2+c^2-2bc+b^2))/a

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asqrt(x^2+d)+b=c

a x^{2} + d + b = c

x = \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}, x = - \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}

Solution steps

a x^{2} + d + b = c

Move

b

to the right side

a x^{2} + d = c - b

Divide both sides by

a

x^{2} + d = \frac{c - b}{a}

Square both sides:

x^{2} + d = \frac{c ^{2}}{a ^{2}} - \frac{2 b c}{a ^{2}} + \frac{b ^{2}}{a ^{2}}

x^{2} + d = \frac{c ^{2}}{a ^{2}} - \frac{2 b c}{a ^{2}} + \frac{b ^{2}}{a ^{2}}

Solve

x^{2} + d = \frac{c ^{2}}{a ^{2}} - \frac{2 b c}{a ^{2}} + \frac{b ^{2}}{a ^{2}} : x = \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}, x = - \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}

x = \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}, x = - \frac{- d a ^{2} + c ^{2} - 2 b c + b ^{2}}{a}

x = 2 x

3 x - 4 - x = 3

\frac{53 + 5 z}{7} = 2

- x + 1.7 = 11.7

x, y = - 16 - x^{2}

What is the answer to asqrt(x^2+d)+b=c ?
The answer to asqrt(x^2+d)+b=c is x=(sqrt(-da^2+c^2-2bc+b^2))/a ,x=-(sqrt(-da^2+c^2-2bc+b^2))/a