What is the answer to sqrt(x^2+2^2)=6x+1 ?

The answer to sqrt(x^2+2^2)=6x+1 is x=(-6+sqrt(141))/(35)

Solve for x: sqrt(x^2+2^2)=6x+1

The solution is x=(-6+sqrt(141))/(35)

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x^{2} + 2^{2} = 6 x + 1

x = \frac{- 6 + 141}{35}

Decimal Notation

x = 0.16783 \dots

Solution steps

x^{2} + 2^{2} = 6 x + 1

Square both sides:

x^{2} + 4 = 36 x^{2} + 12 x + 1

x^{2} + 4 = 36 x^{2} + 12 x + 1

Solve

x^{2} + 4 = 36 x^{2} + 12 x + 1 : x = \frac{- 6 + 141}{35}, x = - \frac{6 + 141}{35}

x = \frac{- 6 + 141}{35}, x = - \frac{6 + 141}{35}

Verify Solutions:

x = \frac{- 6 + 141}{35}

True

, x = - \frac{6 + 141}{35}

False

The solution is

x = \frac{- 6 + 141}{35}

x = 3 x

2 z + 3 = - z

x - 1 - x = - 1

2 x 1 - x^{2} = x

48 + 2 x = x

What is the answer to sqrt(x^2+2^2)=6x+1 ?
The answer to sqrt(x^2+2^2)=6x+1 is x=(-6+sqrt(141))/(35)
Solve for x: sqrt(x^2+2^2)=6x+1
The solution is x=(-6+sqrt(141))/(35)