What is the answer to sqrt(2x^2-5x+12)=x-4 ?

The answer to sqrt(2x^2-5x+12)=x-4 is No Solution for x\in\mathbb{R}

Solve for x: sqrt(2x^2-5x+12)=x-4

The solution is No Solution for x\in\mathbb{R}

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2 x^{2} - 5 x + 12 = x - 4

No Solution for x \in R

Solution steps

2 x^{2} - 5 x + 12 = x - 4

Square both sides:

2 x^{2} - 5 x + 12 = x^{2} - 8 x + 16

2 x^{2} - 5 x + 12 = x^{2} - 8 x + 16

Solve

2 x^{2} - 5 x + 12 = x^{2} - 8 x + 16 : x = 1, x = - 4

x = 1, x = - 4

Verify Solutions:

x = 1

False

, x = - 4

False

The solution is

No Solution for x \in R

x^{\frac{1}{2}} + x^{- 1} = 110

2 x - 9 = x

5 + 4 x + 2 x + 3 = 2

What is the answer to sqrt(2x^2-5x+12)=x-4 ?
The answer to sqrt(2x^2-5x+12)=x-4 is No Solution for x\in\mathbb{R}
Solve for x: sqrt(2x^2-5x+12)=x-4
The solution is No Solution for x\in\mathbb{R}