What is the answer to \sqrt[3]{2x+1}=2 ?

The answer to \sqrt[3]{2x+1}=2 is x= 7/2

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\sqrt[3]{2x+1}=2

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

Take both sides of the equation to the power of

3 : 2 x + 1 = 8

2 x + 1 = 8

Solve

2 x + 1 = 8 : x = \frac{7}{2}

x = \frac{7}{2}

Verify Solutions:

x = \frac{7}{2}

True

The solution is

x = \frac{7}{2}

(4 C)^{0.5} = 0.5 C

x + 3 + x = 3

(5 - x)^{\frac{1}{2}} - 2 x = 0

What is the answer to \sqrt[3]{2x+1}=2 ?
The answer to \sqrt[3]{2x+1}=2 is x= 7/2
Solve for x: \sqrt[3]{2x+1}=2
The solution is x= 7/2