What are the solutions to the equation 2x^2+8x-960=0 ?

The solutions to the equation 2x^2+8x-960=0 are x=20,x=-24

Find the zeros of 2x^2+8x-960=0

The zeros of 2x^2+8x-960=0 are x=20,x=-24

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2 x^{2} + 8 x - 960 = 0

x = 20, x = - 24

Solution steps

2 x^{2} + 8 x - 960 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 960 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 960) = 88

x_{1, 2} = \frac{- 8 \pm 88}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 88}{2 \cdot 2}, x_{2} = \frac{- 8 - 88}{2 \cdot 2}

x = \frac{- 8 + 88}{2 \cdot 2} : 20

x = \frac{- 8 - 88}{2 \cdot 2} : - 24

The solutions to the quadratic equation are:

x = 20, x = - 24

i (5 + 7 i)

0.2 x^{2} + 0.4 x - 0.3 = 0

a - 5 \geq - 9

(12 x^{\frac{1}{2}})^{2}

(ab)^{- 2}

What are the solutions to the equation 2x^2+8x-960=0 ?
The solutions to the equation 2x^2+8x-960=0 are x=20,x=-24
Find the zeros of 2x^2+8x-960=0
The zeros of 2x^2+8x-960=0 are x=20,x=-24