What is the answer to sqrt(2x^2-1)=sqrt(x) ?

The answer to sqrt(2x^2-1)=sqrt(x) is x=1,x=-1/2

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sqrt(2x^2-1)=sqrt(x)

2 x^{2} - 1 = x

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

2 x^{2} - 1 = x

Square both sides:

2 x^{2} - 1 = x

2 x^{2} - 1 = x

Solve

2 x^{2} - 1 = x : x = 1, x = - \frac{1}{2}

x = 1, x = - \frac{1}{2}

Verify Solutions:

x = 1

True

, x = - \frac{1}{2}

True

The solutions are

x = 1, x = - \frac{1}{2}

x + x + 1 = 2

x - 4 = 17 x + 16

2 = \frac{1}{x}

x + 2 11 - x = 3

7 x = 6 x + 2

What is the answer to sqrt(2x^2-1)=sqrt(x) ?
The answer to sqrt(2x^2-1)=sqrt(x) is x=1,x=-1/2
Solve for x: sqrt(2x^2-1)=sqrt(x)
The solution is x=1,x=-1/2