What is the answer to solvefor x,xy-sqrt(4-x^2)=0 ?

The answer to solvefor x,xy-sqrt(4-x^2)=0 is x= 2/(sqrt(1+y^2)) {y>= 0},x=-2/(sqrt(1+y^2)) {y<= 0}

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solvefor x,xy-sqrt(4-x^2)=0

solve for

x, x y - 4 - x^{2} = 0

x = \frac{2}{1 + y ^{2}} {y \geq 0}, x = - \frac{2}{1 + y ^{2}} {y \leq 0}

Solution steps

x y - 4 - x^{2} = 0

Remove square roots

4 - x^{2} = x^{2} y^{2}

Solve

4 - x^{2} = x^{2} y^{2} : x = \frac{2}{1 + y ^{2}}, x = - \frac{2}{1 + y ^{2}}

x = \frac{2}{1 + y ^{2}}, x = - \frac{2}{1 + y ^{2}}

Verify Solutions:

x = \frac{2}{1 + y ^{2}} {y \geq 0}, x = - \frac{2}{1 + y ^{2}} {y \leq 0}

The solutions are

x = \frac{2}{1 + y ^{2}} {y \geq 0}, x = - \frac{2}{1 + y ^{2}} {y \leq 0}

7 = x

t^{\frac{2}{3}} = 9

3.6 = 1.5 - 0.7 z^{1.5} - 0.7 z

x + 5 = x + 1

x + 2 = 4 - x

What is the answer to solvefor x,xy-sqrt(4-x^2)=0 ?
The answer to solvefor x,xy-sqrt(4-x^2)=0 is x= 2/(sqrt(1+y^2)) {y>= 0},x=-2/(sqrt(1+y^2)) {y<= 0}