What is the answer to (sqrt(b^2-98))/7 =2 ?

The answer to (sqrt(b^2-98))/7 =2 is b=7sqrt(6),b=-7sqrt(6)

Solve for b: (sqrt(b^2-98))/7 =2

The solution is b=7sqrt(6),b=-7sqrt(6)

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\frac{b ^{2} - 98}{7} = 2

b = 76, b = - 76

Decimal Notation

b = 17.14642 \dots, b = - 17.14642 \dots

Solution steps

\frac{b ^{2} - 98}{7} = 2

Multiply both sides by

7

\frac{b ^{2} - 98}{7} \cdot 7 = 2 \cdot 7

Simplify

b^{2} - 98 = 14

Square both sides:

b^{2} - 98 = 196

b^{2} - 98 = 196

Solve

b^{2} - 98 = 196 : b = 76, b = - 76

b = 76, b = - 76

Verify Solutions:

b = 76

True

, b = - 76

True

The solutions are

b = 76, b = - 76

13 1 + x^{2} = 10 + 24 x

0 = 4 - x

x^{2} + 5 = 3 - x

9 + 8 x + 6 x + 7 = 2

3 x + 40 = x

What is the answer to (sqrt(b^2-98))/7 =2 ?
The answer to (sqrt(b^2-98))/7 =2 is b=7sqrt(6),b=-7sqrt(6)
Solve for b: (sqrt(b^2-98))/7 =2
The solution is b=7sqrt(6),b=-7sqrt(6)