What is the answer to sqrt(x+4)-x=1 ?

The answer to sqrt(x+4)-x=1 is x=(-1+sqrt(13))/2

Solve for x: sqrt(x+4)-x=1

The solution is x=(-1+sqrt(13))/2

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x + 4 - x = 1

x = \frac{- 1 + 13}{2}

Decimal Notation

x = 1.30277 \dots

Solution steps

x + 4 - x = 1

Remove square roots

x + 4 = 1 + 2 x + x^{2}

Solve

x + 4 = 1 + 2 x + x^{2} : x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Verify Solutions:

x = \frac{- 1 + 13}{2}

True

, x = \frac{- 1 - 13}{2}

False

The solution is

x = \frac{- 1 + 13}{2}

x + 3 = 8

x + 47 = x + 5

12.56 = 2 π \frac{l}{32}

x + 9 - 3 = 6

6 + 4 x - 19 = x

What is the answer to sqrt(x+4)-x=1 ?
The answer to sqrt(x+4)-x=1 is x=(-1+sqrt(13))/2
Solve for x: sqrt(x+4)-x=1
The solution is x=(-1+sqrt(13))/2