What is the answer to sqrt(11-2x)=sqrt(x^2+4x+4) ?

The answer to sqrt(11-2x)=sqrt(x^2+4x+4) is x=1,x=-7

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sqrt(11-2x)=sqrt(x^2+4x+4)

11 - 2 x = x^{2} + 4 x + 4

x = 1, x = - 7

Solution steps

11 - 2 x = x^{2} + 4 x + 4

Square both sides:

11 - 2 x = x^{2} + 4 x + 4

11 - 2 x = x^{2} + 4 x + 4

Solve

11 - 2 x = x^{2} + 4 x + 4 : x = 1, x = - 7

x = 1, x = - 7

Verify Solutions:

x = 1

True

, x = - 7

True

The solutions are

x = 1, x = - 7

x + 2 + 1 = 3 x + 3

47 - x - 2 = 4

2 x^{\frac{3}{2}} = \frac{2}{125}

x = - 9 + 6 x

5 x = 2 x - 3

What is the answer to sqrt(11-2x)=sqrt(x^2+4x+4) ?
The answer to sqrt(11-2x)=sqrt(x^2+4x+4) is x=1,x=-7
Solve for x: sqrt(11-2x)=sqrt(x^2+4x+4)
The solution is x=1,x=-7