What is the answer to sqrt(2x+1)=sqrt(3x-5) ?

The answer to sqrt(2x+1)=sqrt(3x-5) is x=6

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sqrt(2x+1)=sqrt(3x-5)

2 x + 1 = 3 x - 5

x = 6

Solution steps

2 x + 1 = 3 x - 5

Square both sides:

2 x + 1 = 3 x - 5

2 x + 1 = 3 x - 5

Solve

2 x + 1 = 3 x - 5 : x = 6

x = 6

Verify Solutions:

x = 6

True

The solution is

x = 6

x = x - 1

9 - 7 x + 6 = 10

4 t + 5 = 3 - t + 5

(x - 5)^{\frac{3}{4}} - 8 = 0

4 = x^{2}

What is the answer to sqrt(2x+1)=sqrt(3x-5) ?
The answer to sqrt(2x+1)=sqrt(3x-5) is x=6
Solve for x: sqrt(2x+1)=sqrt(3x-5)
The solution is x=6