What is the answer to 5+\sqrt[3]{x^3+7}=3x^2+4x ?

The answer to 5+\sqrt[3]{x^3+7}=3x^2+4x is x=1,x=-2

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5+\sqrt[3]{x^3+7}=3x^2+4x

x = 1, x = - 2

Solution steps

Remove roots

x^{3} + 7 = 27 x^{6} + 108 x^{5} + 9 x^{4} - 296 x^{3} - 15 x^{2} + 300 x - 125

Solve

x^{3} + 7 = 27 x^{6} + 108 x^{5} + 9 x^{4} - 296 x^{3} - 15 x^{2} + 300 x - 125 : x = 1, x = - 2

x = 1, x = - 2

Verify Solutions:

x = 1

True

, x = - 2

True

The solutions are

x = 1, x = - 2

6 d - 11 + 8 = 11

x + x = 3

6 - 5 x - x = 0

2 x - 1 = x - 1

29.4 = 17.29 \cdot x^{1.5}

What is the answer to 5+\sqrt[3]{x^3+7}=3x^2+4x ?
The answer to 5+\sqrt[3]{x^3+7}=3x^2+4x is x=1,x=-2
Solve for x: 5+\sqrt[3]{x^3+7}=3x^2+4x
The solution is x=1,x=-2