What is the answer to sqrt(x^2-x-6)=x+3 ?

The answer to sqrt(x^2-x-6)=x+3 is x=-15/7

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sqrt(x^2-x-6)=x+3

x^{2} - x - 6 = x + 3

x = - \frac{15}{7}

Decimal Notation

x = - 2.14285 \dots

Solution steps

x^{2} - x - 6 = x + 3

Square both sides:

x^{2} - x - 6 = x^{2} + 6 x + 9

x^{2} - x - 6 = x^{2} + 6 x + 9

Solve

x^{2} - x - 6 = x^{2} + 6 x + 9 : x = - \frac{15}{7}

x = - \frac{15}{7}

Verify Solutions:

x = - \frac{15}{7}

True

The solution is

x = - \frac{15}{7}

- 9 4 g + 13 = - 45

x = 2 x^{2} - 15

x + 10 = - 5

12 + 4 x + 2 x + 10 = 2

x^{4} = x^{2}

What is the answer to sqrt(x^2-x-6)=x+3 ?
The answer to sqrt(x^2-x-6)=x+3 is x=-15/7
Solve for x: sqrt(x^2-x-6)=x+3
The solution is x=-15/7