What is the answer to x^2-sqrt(5x)+1=0 ?

The answer to x^2-sqrt(5x)+1=0 is x\approx 0.21978…,x\approx 1.20683…

Solve for x: x^2-sqrt(5x)+1=0

The solution is x\approx 0.21978…,x\approx 1.20683…

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x^{2} - 5 x + 1 = 0

x \approx 0.21978 \dots, x \approx 1.20683 \dots

Solution steps

x^{2} - 5 x + 1 = 0

Remove square roots

5 x = x^{4} + 2 x^{2} + 1

Solve

5 x = x^{4} + 2 x^{2} + 1 : x \approx 0.21978 \dots, x \approx 1.20683 \dots

x \approx 0.21978 \dots, x \approx 1.20683 \dots

Verify Solutions:

x \approx 0.21978 \dots

True

, x \approx 1.20683 \dots

True

The solutions are

x \approx 0.21978 \dots, x \approx 1.20683 \dots

x + 6 = 8

x + 6 = 0

x - 3 = x - 3

x + 2 = 8 x - 7

5 + x + 2 x - 4 = 5

What is the answer to x^2-sqrt(5x)+1=0 ?
The answer to x^2-sqrt(5x)+1=0 is x\approx 0.21978…,x\approx 1.20683…
Solve for x: x^2-sqrt(5x)+1=0
The solution is x\approx 0.21978…,x\approx 1.20683…