What is the answer to solvefor y,y^{-1/3}=x ?

The answer to solvefor y,y^{-1/3}=x is y= 1/(x^3) {x 0}

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solvefor y,y^{-1/3}=x

solve for

y, y^{- \frac{1}{3}} = x

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

Solution steps

y^{- \frac{1}{3}} = x

Take both sides of the equation to the power of

- 3 : y = \frac{1}{x ^{3}}

y = \frac{1}{x ^{3}}

Verify Solutions:

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

The solution is

y = \frac{1}{x ^{3}} {x < 0 or x > 0}

3 x^{2} + 3 x + 2 = 2 x x + 3

3 x + 8 = x + 4

x = \frac{3 x}{2}

(x^{3})^{\frac{2}{3}} = 9

85300 = 50370 (1 + X)^{1.16}

What is the answer to solvefor y,y^{-1/3}=x ?
The answer to solvefor y,y^{-1/3}=x is y= 1/(x^3) {x<0\lor x>0}