What is the answer to 5=sqrt((-1-x)^2+(-2-2)^2) ?

The answer to 5=sqrt((-1-x)^2+(-2-2)^2) is x=2,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5=sqrt((-1-x)^2+(-2-2)^2)

5 = (- 1 - x)^{2} + (- 2 - 2)^{2}

x = 2, x = - 4

Solution steps

5 = (- 1 - x)^{2} + (- 2 - 2)^{2}

Square both sides:

25 = x^{2} + 2 x + 17

25 = x^{2} + 2 x + 17

Solve

25 = x^{2} + 2 x + 17 : x = 2, x = - 4

x = 2, x = - 4

Verify Solutions:

x = 2

True

, x = - 4

True

The solutions are

x = 2, x = - 4

0.75 = 2 π \frac{8}{x}

4 x - 3 = 2 + 2 x - 5

8 = 5 c^{\frac{1}{5}}

x + 4 = x - 1 + 1

What is the answer to 5=sqrt((-1-x)^2+(-2-2)^2) ?
The answer to 5=sqrt((-1-x)^2+(-2-2)^2) is x=2,x=-4
Solve for x: 5=sqrt((-1-x)^2+(-2-2)^2)
The solution is x=2,x=-4