What is the answer to sqrt(2x-1)=\sqrt[4]{3x-2} ?

The answer to sqrt(2x-1)=\sqrt[4]{3x-2} is x=1,x= 3/4

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sqrt(2x-1)=\sqrt[4]{3x-2}

x = 1, x = \frac{3}{4}

Decimal Notation

x = 1, x = 0.75

Solution steps

Take both sides of the equation to the power of

4 : (2 x - 1)^{2} = 3 x - 2

(2 x - 1)^{2} = 3 x - 2

Solve

(2 x - 1)^{2} = 3 x - 2 : x = 1, x = \frac{3}{4}

x = 1, x = \frac{3}{4}

Verify Solutions:

x = 1

True

, x = \frac{3}{4}

True

The solutions are

x = 1, x = \frac{3}{4}

600 = x^{\frac{2}{3}}

v = 6 v - 8

x - 1 - x = - 5

2 t - 3 = 11

4 x^{2} - 3 x - 2 = 2 x - 1

What is the answer to sqrt(2x-1)=\sqrt[4]{3x-2} ?
The answer to sqrt(2x-1)=\sqrt[4]{3x-2} is x=1,x= 3/4
Solve for x: sqrt(2x-1)=\sqrt[4]{3x-2}
The solution is x=1,x= 3/4