What are the solutions to the equation 25a^2-40a=-16 ?

The solutions to the equation 25a^2-40a=-16 are a= 4/5

Find the zeros of 25a^2-40a=-16

The zeros of 25a^2-40a=-16 are a= 4/5

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25 a^{2} - 40 a = - 16

a = \frac{4}{5}

Solution steps

25 a^{2} - 40 a = - 16

Move

16

to the left side

25 a^{2} - 40 a + 16 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

a_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

a = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

a = \frac{4}{5}

The solution to the quadratic equation is:

a = \frac{4}{5}

\frac{2}{5} x + \frac{4}{5} = - \frac{8}{5}

\frac{7 x + 3}{x - 1} = 4

7 \cdot 6

- 5 (w - 1) \leq 45

8 x + 16 = - 9

What are the solutions to the equation 25a^2-40a=-16 ?
The solutions to the equation 25a^2-40a=-16 are a= 4/5
Find the zeros of 25a^2-40a=-16
The zeros of 25a^2-40a=-16 are a= 4/5