What is the answer to sqrt(x(x+3))=sqrt(x^2+3x) ?

The answer to sqrt(x(x+3))=sqrt(x^2+3x) is x = 0

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sqrt(x(x+3))=sqrt(x^2+3x)

x (x + 3) = x^{2} + 3 x

x \leq - 3 or x \geq 0

Solution steps

x (x + 3) = x^{2} + 3 x

Square both sides:

x^{2} + 3 x = x^{2} + 3 x

x^{2} + 3 x = x^{2} + 3 x

Both sides are equal

True for all x

Verify Solutions:

x < - 3

True

, x = - 3

True

, x = 0

True

, x > 0

True

The solution is

x \leq - 3 or x \geq 0

q, 5 = 5 q^{- 0.5}

5 + x = 25 + x^{2}

x + 7 - x = 11

2 x + 5 = 2 x + 1

What is the answer to sqrt(x(x+3))=sqrt(x^2+3x) ?
The answer to sqrt(x(x+3))=sqrt(x^2+3x) is x<=-3\lor x>= 0
Solve for x: sqrt(x(x+3))=sqrt(x^2+3x)
The solution is x<=-3\lor x>= 0