What is the answer to a(x)=sqrt(x+3) ?

The answer to a(x)=sqrt(x+3) is x=(1+sqrt(1+12a^2))/(2a^2),x=(1-sqrt(1+12a^2))/(2a^2) {a 0}

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a(x)=sqrt(x+3)

a (x) = x + 3

x = \frac{1 + 1 + 12 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 12 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

Solution steps

a (x) = x + 3

Square both sides:

a^{2} x^{2} = x + 3

a^{2} x^{2} = x + 3

Solve

a^{2} x^{2} = x + 3 : x = \frac{1 + 1 + 12 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 12 a ^{2}}{2 a ^{2}}

x = \frac{1 + 1 + 12 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 12 a ^{2}}{2 a ^{2}}

Verify Solutions:

x = \frac{1 + 1 + 12 a ^{2}}{2 a ^{2}}

True

, x = \frac{1 - 1 + 12 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

The solutions are

x = \frac{1 + 1 + 12 a ^{2}}{2 a ^{2}}, x = \frac{1 - 1 + 12 a ^{2}}{2 a ^{2}} {a < 0 or a > 0}

1 + \frac{1}{x} = 0

4 + 5 x - 6 = x

4 x + 1 = 11

x - 6 = 3

x - 6 = 4

What is the answer to a(x)=sqrt(x+3) ?
The answer to a(x)=sqrt(x+3) is x=(1+sqrt(1+12a^2))/(2a^2),x=(1-sqrt(1+12a^2))/(2a^2) {a<0\lor a>0}