What is the answer to 3=sqrt(2^2+y^2) ?

The answer to 3=sqrt(2^2+y^2) is y=sqrt(5),y=-sqrt(5)

Solve for y: 3=sqrt(2^2+y^2)

The solution is y=sqrt(5),y=-sqrt(5)

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3 = 2^{2} + y^{2}

y = 5, y = - 5

Solution steps

3 = 2^{2} + y^{2}

Square both sides:

9 = 4 + y^{2}

9 = 4 + y^{2}

Solve

9 = 4 + y^{2} : y = 5, y = - 5

y = 5, y = - 5

Verify Solutions:

y = 5

True

, y = - 5

True

The solutions are

y = 5, y = - 5

- x = 8

x + 9 - x = 3

x + 5 = 4 x - 13

x = - 4 x + 21

2 x + 5 = 4 x^{2} + 45

What is the answer to 3=sqrt(2^2+y^2) ?
The answer to 3=sqrt(2^2+y^2) is y=sqrt(5),y=-sqrt(5)
Solve for y: 3=sqrt(2^2+y^2)
The solution is y=sqrt(5),y=-sqrt(5)