What is the answer to solvefor x,ysqrt(5-2x)-3=-0 ?

The answer to solvefor x,ysqrt(5-2x)-3=-0 is x=-(9-5y^2)/(2y^2) {y 0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,ysqrt(5-2x)-3=-0

solve for

x, y 5 - 2 x - 3 = - 0

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

Solution steps

y 5 - 2 x - 3 = - 0

y 5 - 2 x - 3 = 0

Move

3

to the right side

y 5 - 2 x = 3

Divide both sides by

y

5 - 2 x = \frac{3}{y}

Square both sides:

5 - 2 x = \frac{9}{y ^{2}}

5 - 2 x = \frac{9}{y ^{2}}

Solve

5 - 2 x = \frac{9}{y ^{2}} : x = - \frac{9 - 5 y ^{2}}{2 y ^{2}}

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}}

Verify Solutions:

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

The solution is

x = - \frac{9 - 5 y ^{2}}{2 y ^{2}} {y < 0 or y > 0}

2 - 7 x + 2 = 5 x + 1 + 3

x + 6 = - 2

3 x + 4 + 1 = 5 x + 5

x + 4 - x + 2 = 2

What is the answer to solvefor x,ysqrt(5-2x)-3=-0 ?
The answer to solvefor x,ysqrt(5-2x)-3=-0 is x=-(9-5y^2)/(2y^2) {y<0\lor y>0}