What are the solutions to the equation 7p^2=8p-3 ?

The solutions to the equation 7p^2=8p-3 are p= 4/7+i(sqrt(5))/7 ,p= 4/7-i(sqrt(5))/7

Find the zeros of 7p^2=8p-3

The zeros of 7p^2=8p-3 are p= 4/7+i(sqrt(5))/7 ,p= 4/7-i(sqrt(5))/7

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7 p^{2} = 8 p - 3

p = \frac{4}{7} + i \frac{5}{7}, p = \frac{4}{7} - i \frac{5}{7}

Solution steps

7 p^{2} = 8 p - 3

Move

3

to the left side

7 p^{2} + 3 = 8 p

Move

8 p

to the left side

7 p^{2} + 3 - 8 p = 0

Write in the standard form

a x^{2} + b x + c = 0

7 p^{2} - 8 p + 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

Simplify

(- 8)^{2} - 4 \cdot 7 \cdot 3 : 25 i

p_{1, 2} = \frac{- ( - 8 ) \pm 2 5 i}{2 \cdot 7}

Separate the solutions

p_{1} = \frac{- ( - 8 ) + 2 5 i}{2 \cdot 7}, p_{2} = \frac{- ( - 8 ) - 2 5 i}{2 \cdot 7}

p = \frac{- ( - 8 ) + 2 5 i}{2 \cdot 7} : \frac{4}{7} + i \frac{5}{7}

p = \frac{- ( - 8 ) - 2 5 i}{2 \cdot 7} : \frac{4}{7} - i \frac{5}{7}

The solutions to the quadratic equation are:

p = \frac{4}{7} + i \frac{5}{7}, p = \frac{4}{7} - i \frac{5}{7}

7

5 \leq m + 4 < 10

\frac{13}{3} + \frac{17}{3}

\frac{1}{35}

- 6 - 5 v < - 2 v - 5 v

What are the solutions to the equation 7p^2=8p-3 ?
The solutions to the equation 7p^2=8p-3 are p= 4/7+i(sqrt(5))/7 ,p= 4/7-i(sqrt(5))/7
Find the zeros of 7p^2=8p-3
The zeros of 7p^2=8p-3 are p= 4/7+i(sqrt(5))/7 ,p= 4/7-i(sqrt(5))/7