What is the answer to (x^2-25)sqrt(4-x)=0 ?

The answer to (x^2-25)sqrt(4-x)=0 is x=4,x=-5

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(x^2-25)sqrt(4-x)=0

(x^{2} - 25) 4 - x = 0

x = 4, x = - 5

Solution steps

(x^{2} - 25) 4 - x = 0

Factor

(x^{2} - 25) 4 - x : 4 - x (x + 5) (x - 5)

4 - x (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 - x = 0 or x + 5 = 0 or x - 5 = 0

Solve

4 - x = 0 : x = 4

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

x = 4, x = - 5, x = 5

Verify Solutions:

x = 4

True

, x = - 5

True

, x = 5

False

The solutions are

x = 4, x = - 5

x - 16 = 6

x + 6 + x = 8

y^{\frac{1}{2}} = y

3 + x + 3 = 6

2 x - 6 = 5 x - 15

What is the answer to (x^2-25)sqrt(4-x)=0 ?
The answer to (x^2-25)sqrt(4-x)=0 is x=4,x=-5
Solve for x: (x^2-25)sqrt(4-x)=0
The solution is x=4,x=-5