What is the answer to sqrt(x^2-x-3)=x+3 ?

The answer to sqrt(x^2-x-3)=x+3 is x=-12/7

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sqrt(x^2-x-3)=x+3

x^{2} - x - 3 = x + 3

x = - \frac{12}{7}

Decimal Notation

x = - 1.71428 \dots

Solution steps

x^{2} - x - 3 = x + 3

Square both sides:

x^{2} - x - 3 = x^{2} + 6 x + 9

x^{2} - x - 3 = x^{2} + 6 x + 9

Solve

x^{2} - x - 3 = x^{2} + 6 x + 9 : x = - \frac{12}{7}

x = - \frac{12}{7}

Verify Solutions:

x = - \frac{12}{7}

True

The solution is

x = - \frac{12}{7}

2 (12 p + 28)^{\frac{1}{4}} - 15 = - 7

3^{2} + (- 1) + x^{2} = 1

4 = \frac{3 v}{π ^{8}}

0.6 = x^{0.75}

x - 1 - 2 = 4

What is the answer to sqrt(x^2-x-3)=x+3 ?
The answer to sqrt(x^2-x-3)=x+3 is x=-12/7
Solve for x: sqrt(x^2-x-3)=x+3
The solution is x=-12/7