What is the answer to sqrt(4x)-2=sqrt(10x+6) ?

The answer to sqrt(4x)-2=sqrt(10x+6) is No Solution for x\in\mathbb{R}

Solve for x: sqrt(4x)-2=sqrt(10x+6)

The solution is No Solution for x\in\mathbb{R}

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4 x - 2 = 10 x + 6

No Solution for x \in R

Solution steps

4 x - 2 = 10 x + 6

Remove square roots

64 x = 36 x^{2} + 24 x + 4

Solve

64 x = 36 x^{2} + 24 x + 4 : x = 1, x = \frac{1}{9}

x = 1, x = \frac{1}{9}

Verify Solutions:

x = 1

False

, x = \frac{1}{9}

False

The solution is

No Solution for x \in R

(2 x^{2} + 8)^{\frac{1}{4}} = x

4 x + 20 = x + 2

x = 24

2 t + 3 = - 3

What is the answer to sqrt(4x)-2=sqrt(10x+6) ?
The answer to sqrt(4x)-2=sqrt(10x+6) is No Solution for x\in\mathbb{R}
Solve for x: sqrt(4x)-2=sqrt(10x+6)
The solution is No Solution for x\in\mathbb{R}