What is the answer to solvefor x,sqrt(x)+4=x ?

The answer to solvefor x,sqrt(x)+4=x is x=(9+sqrt(17))/2

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solvefor x,sqrt(x)+4=x

x, x + 4 = x

x = \frac{9 + 17}{2}

Decimal Notation

x = 6.56155 \dots

Solution steps

x + 4 = x

Remove square roots

x = x^{2} - 8 x + 16

Solve

x = x^{2} - 8 x + 16 : x = \frac{9 + 17}{2}, x = \frac{9 - 17}{2}

x = \frac{9 + 17}{2}, x = \frac{9 - 17}{2}

Verify Solutions:

x = \frac{9 + 17}{2}

True

, x = \frac{9 - 17}{2}

False

The solution is

x = \frac{9 + 17}{2}

x^{\frac{1}{2}} = x - 2

w, 29 + 4 w = 23 - c w

12 = 3 m + 36 m^{2} + 9

5 = (100 x^{0.25}) (x + 300)^{- 0.25}

x^{- \frac{6}{8}} = 0.001

What is the answer to solvefor x,sqrt(x)+4=x ?
The answer to solvefor x,sqrt(x)+4=x is x=(9+sqrt(17))/2