What is the answer to (sqrt(2x-5))(3x+2)=0 ?

The answer to (sqrt(2x-5))(3x+2)=0 is x= 5/2

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(sqrt(2x-5))(3x+2)=0

(2 x - 5) (3 x + 2) = 0

x = \frac{5}{2}

Solution steps

(2 x - 5) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or 3 x + 2 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

x = \frac{5}{2}, x = - \frac{2}{3}

Verify Solutions:

x = \frac{5}{2}

True

, x = - \frac{2}{3}

False

The solution is

x = \frac{5}{2}

28 - 3 x - x = 0

5 x - 15 - x + 1 = 2

x = 7 x - 10

8 x - 11 = x + 3

What is the answer to (sqrt(2x-5))(3x+2)=0 ?
The answer to (sqrt(2x-5))(3x+2)=0 is x= 5/2
Solve for x: (sqrt(2x-5))(3x+2)=0
The solution is x= 5/2