What is the answer to sqrt(y^2+5)=y^2+1 ?

The answer to sqrt(y^2+5)=y^2+1 is y=sqrt((-1+\sqrt{17))/2},y=-sqrt((-1+\sqrt{17))/2}

Solve for y: sqrt(y^2+5)=y^2+1

The solution is y=sqrt((-1+\sqrt{17))/2},y=-sqrt((-1+\sqrt{17))/2}

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y^{2} + 5 = y^{2} + 1

y = \frac{- 1 + 17}{2}, y = - \frac{- 1 + 17}{2}

Solution steps

y^{2} + 5 = y^{2} + 1

Square both sides:

y^{2} + 5 = y^{4} + 2 y^{2} + 1

y^{2} + 5 = y^{4} + 2 y^{2} + 1

Solve

y^{2} + 5 = y^{4} + 2 y^{2} + 1 : y = \frac{- 1 + 17}{2}, y = - \frac{- 1 + 17}{2}

y = \frac{- 1 + 17}{2}, y = - \frac{- 1 + 17}{2}

Verify Solutions:

y = \frac{- 1 + 17}{2}

True

, y = - \frac{- 1 + 17}{2}

True

The solutions are

y = \frac{- 1 + 17}{2}, y = - \frac{- 1 + 17}{2}

x - 2 - 4 = - x

12 + 2 x - 1 = 4

x - 5 = 14 x + 25

u = 7

u = 8

What is the answer to sqrt(y^2+5)=y^2+1 ?
The answer to sqrt(y^2+5)=y^2+1 is y=sqrt((-1+\sqrt{17))/2},y=-sqrt((-1+\sqrt{17))/2}
Solve for y: sqrt(y^2+5)=y^2+1
The solution is y=sqrt((-1+\sqrt{17))/2},y=-sqrt((-1+\sqrt{17))/2}