What is the answer to sqrt(2x-1)=2+sqrt(x-4) ?

The answer to sqrt(2x-1)=2+sqrt(x-4) is x=13,x=5

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sqrt(2x-1)=2+sqrt(x-4)

2 x - 1 = 2 + x - 4

x = 13, x = 5

Solution steps

2 x - 1 = 2 + x - 4

Remove square roots

x^{2} - 2 x + 1 = 16 x - 64

Solve

x^{2} - 2 x + 1 = 16 x - 64 : x = 13, x = 5

x = 13, x = 5

Verify Solutions:

x = 13

True

, x = 5

True

The solutions are

x = 13, x = 5

0 = - 0.05 k + 1.6 k^{0.5} + 6.4

\frac{2}{3 x ^{\frac{1}{3}}} = 1

8 = 4 t^{3}

What is the answer to sqrt(2x-1)=2+sqrt(x-4) ?
The answer to sqrt(2x-1)=2+sqrt(x-4) is x=13,x=5
Solve for x: sqrt(2x-1)=2+sqrt(x-4)
The solution is x=13,x=5