What is the answer to n^2=sqrt(-1-2n)^2 ?

The answer to n^2=sqrt(-1-2n)^2 is n=-1

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n^2=sqrt(-1-2n)^2

n^{2} = - 1 - 2 n^{2}

n = - 1

Solution steps

n^{2} = (- 1 - 2 n)^{2}

Move

(- 1 - 2 n)^{2}

to the left side

n^{2} - (- 1 - 2 n)^{2} = 0

Factor

n^{2} - (- 1 - 2 n)^{2} : (n + - 1 - 2 n) (n - - 1 - 2 n)

(n + - 1 - 2 n) (n - - 1 - 2 n) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

n + - 1 - 2 n = 0 or n - - 1 - 2 n = 0

Solve

n + - 1 - 2 n = 0 : n = - 1

Solve

n - - 1 - 2 n = 0 :

No Solution for

n \in R

n = - 1

Verify Solutions:

n = - 1

True

The solution is

n = - 1

v + 9 = 5

x^{2} - 4 x = - 4 + x

3 - x = 0

x + 1 + x + 13 = 6

\frac{2}{4 x - 3} = 1

What is the answer to n^2=sqrt(-1-2n)^2 ?
The answer to n^2=sqrt(-1-2n)^2 is n=-1
Solve for n: n^2=sqrt(-1-2n)^2
The solution is n=-1