What is the answer to \sqrt[3]{(x+1)^2}=4 ?

The answer to \sqrt[3]{(x+1)^2}=4 is x=7,x=-9

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\sqrt[3]{(x+1)^2}=4

x = 7, x = - 9

Solution steps

Take both sides of the equation to the power of

3 : x^{2} + 2 x + 1 = 64

x^{2} + 2 x + 1 = 64

Solve

x^{2} + 2 x + 1 = 64 : x = 7, x = - 9

x = 7, x = - 9

Verify Solutions:

x = 7

True

, x = - 9

True

The solutions are

x = 7, x = - 9

H^{1.53} \cdot 0.535 = 0.04167

3 + 7 x - 3 = x

x + 5 - x = 3

5 x + 11 - 1 = 3

1 + x^{2} = 1 + x

What is the answer to \sqrt[3]{(x+1)^2}=4 ?
The answer to \sqrt[3]{(x+1)^2}=4 is x=7,x=-9
Solve for x: \sqrt[3]{(x+1)^2}=4
The solution is x=7,x=-9