What is the answer to |p-1|=4 ?

The answer to |p-1|=4 is p=-3\lor p=5

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|p-1|=4

∣ p - 1 ∣ = 4

p = - 3 or p = 5

Solution steps

∣ p - 1 ∣ = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

p - 1 = - 4 or p - 1 = 4

p - 1 = - 4 or p - 1 = 4

p = - 3 or p = 5

10 \times 5

3^{3} \cdot 4^{3}

\frac{3}{- 1 + i}

\frac{y - 1}{2} - 2 \leq \frac{3 y - 2}{5}

a^{3} - b^{6}