What is the answer to \sqrt[4]{2x^2}=2x ?

The answer to \sqrt[4]{2x^2}=2x is x=0,x= 1/(2sqrt(2))

Solve for x: \sqrt[4]{2x^2}=2x

The solution is x=0,x= 1/(2sqrt(2))

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Popular >

x = 0, x = \frac{1}{2 2}

Decimal Notation

x = 0, x = 0.35355 \dots

Solution steps

Take both sides of the equation to the power of

4 : 2 x^{2} = 16 x^{4}

2 x^{2} = 16 x^{4}

Solve

2 x^{2} = 16 x^{4} : x = 0, x = - \frac{1}{2 2}, x = \frac{1}{2 2}

x = 0, x = - \frac{1}{2 2}, x = \frac{1}{2 2}

Verify Solutions:

x = 0

True

, x = - \frac{1}{2 2}

False

, x = \frac{1}{2 2}

True

The solutions are

x = 0, x = \frac{1}{2 2}

y + 5 = 2 - y - 4

3 x + 96 + 18 = 27

3 x - 2 - x = 3

13 - x - 7 = 0

6 x + 7 = x + 2

What is the answer to \sqrt[4]{2x^2}=2x ?
The answer to \sqrt[4]{2x^2}=2x is x=0,x= 1/(2sqrt(2))
Solve for x: \sqrt[4]{2x^2}=2x
The solution is x=0,x= 1/(2sqrt(2))