What is the answer to 0=3x^3+4sqrt(1-x)+12 ?

The answer to 0=3x^3+4sqrt(1-x)+12 is x\approx-1.84178…

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0=3x^3+4sqrt(1-x)+12

0 = 3 x^{3} + 4 1 - x + 12

x \approx - 1.84178 \dots

Solution steps

0 = 3 x^{3} + 4 1 - x + 12

Remove square roots

9 x^{6} + 72 x^{3} + 144 = 16 - 16 x

Solve

9 x^{6} + 72 x^{3} + 144 = 16 - 16 x : x \approx - 1.84178 \dots, x \approx - 1.25907 \dots

x \approx - 1.84178 \dots, x \approx - 1.25907 \dots

Verify Solutions:

x \approx - 1.84178 \dots

True

, x \approx - 1.25907 \dots

False

The solution is

x \approx - 1.84178 \dots

x, f = (21 - x)

x + 5 = + (1 - x^{2}) + 4

4 x - 5 x = - 4 x

x, 3 x - 2 y = 40

x + 3 = 2 x - 3

What is the answer to 0=3x^3+4sqrt(1-x)+12 ?
The answer to 0=3x^3+4sqrt(1-x)+12 is x\approx-1.84178…
Solve for x: 0=3x^3+4sqrt(1-x)+12
The solution is x\approx-1.84178…