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Popular >

l(x)=sqrt(x)+x2

Solution

l (x) = x + x 2

Solution

x = \frac{1}{l ^{2} - 4 l + 4} {l < 2 or l > 2}, x = 0

Solution steps

l (x) = x + x \cdot 2

Remove square roots

l^{2} x^{2} - 4 l x^{2} + 4 x^{2} = x

Solve

l^{2} x^{2} - 4 l x^{2} + 4 x^{2} = x : x = \frac{1}{l ^{2} - 4 l + 4}, x = 0

x = \frac{1}{l ^{2} - 4 l + 4}, x = 0

Verify Solutions:

x = \frac{1}{l ^{2} - 4 l + 4} {l < 2 or l > 2}, x = 0

True

The solutions are

x = \frac{1}{l ^{2} - 4 l + 4} {l < 2 or l > 2}, x = 0

Popular Examples

1=sqrt((x-0)^2+(-x-0)^2)

1 = (x - 0)^{2} + (- x - 0)^{2}

h/4 =sqrt(14.7h)+4.9

\frac{h}{4} = 14.7 h + 4.9

x - 2 = 2 x - 4

(7x+1)^{3/2}+6=222

(7 x + 1)^{\frac{3}{2}} + 6 = 222

sqrt(3x+36)+6=x

3 x + 36 + 6 = x

Frequently Asked Questions (FAQ)

What is the answer to l(x)=sqrt(x)+x2 ?
The answer to l(x)=sqrt(x)+x2 is x= 1/(l^2-4l+4) {l<2\lor l>2},x=0