What is the answer to x^2-2x+sqrt(x)=0 ?

The answer to x^2-2x+sqrt(x)=0 is x=0,x=1,x=(3-sqrt(5))/2

Solve for x: x^2-2x+sqrt(x)=0

The solution is x=0,x=1,x=(3-sqrt(5))/2

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x^{2} - 2 x + x = 0

x = 0, x = 1, x = \frac{3 - 5}{2}

Decimal Notation

x = 0, x = 1, x = 0.38196 \dots

Solution steps

x^{2} - 2 x + x = 0

Remove square roots

x = x^{4} - 4 x^{3} + 4 x^{2}

Solve

x = x^{4} - 4 x^{3} + 4 x^{2} : x = 0, x = 1, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

x = 0, x = 1, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Verify Solutions:

x = 0

True

, x = 1

True

, x = \frac{3 + 5}{2}

False

, x = \frac{3 - 5}{2}

True

The solutions are

x = 0, x = 1, x = \frac{3 - 5}{2}

35 \cdot x^{\frac{2}{3}} = 77

2 + 2 x - 3 = x + 7

(x - 2)^{\frac{2}{3}} = 64

(x - 2)^{\frac{2}{3}} = 36

What is the answer to x^2-2x+sqrt(x)=0 ?
The answer to x^2-2x+sqrt(x)=0 is x=0,x=1,x=(3-sqrt(5))/2
Solve for x: x^2-2x+sqrt(x)=0
The solution is x=0,x=1,x=(3-sqrt(5))/2