What is the answer to 5=sqrt((2a-1)^2+(a-3)^2) ?

The answer to 5=sqrt((2a-1)^2+(a-3)^2) is a=3,a=-1

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5=sqrt((2a-1)^2+(a-3)^2)

5 = (2 a - 1)^{2} + (a - 3)^{2}

a = 3, a = - 1

Solution steps

5 = (2 a - 1)^{2} + (a - 3)^{2}

Square both sides:

25 = 5 a^{2} - 10 a + 10

25 = 5 a^{2} - 10 a + 10

Solve

25 = 5 a^{2} - 10 a + 10 : a = 3, a = - 1

a = 3, a = - 1

Verify Solutions:

a = 3

True

, a = - 1

True

The solutions are

a = 3, a = - 1

140 = \frac{1225 a}{1000}

x = 4 x + 21

x - 5 - 4 x = 0

What is the answer to 5=sqrt((2a-1)^2+(a-3)^2) ?
The answer to 5=sqrt((2a-1)^2+(a-3)^2) is a=3,a=-1
Solve for a: 5=sqrt((2a-1)^2+(a-3)^2)
The solution is a=3,a=-1