What is the answer to sqrt(x^2+x-2)=x^2+x-4 ?

The answer to sqrt(x^2+x-2)=x^2+x-4 is x=2,x=-3

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sqrt(x^2+x-2)=x^2+x-4

x^{2} + x - 2 = x^{2} + x - 4

x = 2, x = - 3

Solution steps

x^{2} + x - 2 = x^{2} + x - 4

Square both sides:

x^{2} + x - 2 = x^{4} + 2 x^{3} - 7 x^{2} - 8 x + 16

x^{2} + x - 2 = x^{4} + 2 x^{3} - 7 x^{2} - 8 x + 16

Solve

x^{2} + x - 2 = x^{4} + 2 x^{3} - 7 x^{2} - 8 x + 16 : x = 2, x = - 3, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

x = 2, x = - 3, x = \frac{- 1 + 13}{2}, x = \frac{- 1 - 13}{2}

Verify Solutions:

x = 2

True

, x = - 3

True

, x = \frac{- 1 + 13}{2}

False

, x = \frac{- 1 - 13}{2}

False

The solutions are

x = 2, x = - 3

4 x + 40 = x + 7

73 - n - 116308 n = 0

2 x + 8 - 6 = - 4

4 x + 5 = 2 x - 5

9 w - 15 = 5 w - 3

What is the answer to sqrt(x^2+x-2)=x^2+x-4 ?
The answer to sqrt(x^2+x-2)=x^2+x-4 is x=2,x=-3
Solve for x: sqrt(x^2+x-2)=x^2+x-4
The solution is x=2,x=-3