What is the answer to sqrt(x^2+2x)=sqrt(27-4x) ?

The answer to sqrt(x^2+2x)=sqrt(27-4x) is x=3,x=-9

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sqrt(x^2+2x)=sqrt(27-4x)

x^{2} + 2 x = 27 - 4 x

x = 3, x = - 9

Solution steps

x^{2} + 2 x = 27 - 4 x

Square both sides:

x^{2} + 2 x = 27 - 4 x

x^{2} + 2 x = 27 - 4 x

Solve

x^{2} + 2 x = 27 - 4 x : x = 3, x = - 9

x = 3, x = - 9

Verify Solutions:

x = 3

True

, x = - 9

True

The solutions are

x = 3, x = - 9

5 x + 4 = (x + 4)^{\frac{1}{2}} + 2

2 x - 5 - 3 x + 4 = 1

x + 5 x = 12

188 - 818 = n

1 = (X \cdot 5)^{2} + X^{2}

What is the answer to sqrt(x^2+2x)=sqrt(27-4x) ?
The answer to sqrt(x^2+2x)=sqrt(27-4x) is x=3,x=-9
Solve for x: sqrt(x^2+2x)=sqrt(27-4x)
The solution is x=3,x=-9