What are the solutions to the equation -16t^2+144t+160=0 ?

The solutions to the equation -16t^2+144t+160=0 are t=-1,t=10

Find the zeros of -16t^2+144t+160=0

The zeros of -16t^2+144t+160=0 are t=-1,t=10

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- 16 t^{2} + 144 t + 160 = 0

t = - 1, t = 10

Solution steps

- 16 t^{2} + 144 t + 160 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 ( - 16 ) \cdot 160}{2 ( - 16 )}

14 4^{2} - 4 (- 16) \cdot 160 = 176

t_{1, 2} = \frac{- 144 \pm 176}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 144 + 176}{2 ( - 16 )}, t_{2} = \frac{- 144 - 176}{2 ( - 16 )}

t = \frac{- 144 + 176}{2 ( - 16 )} : - 1

t = \frac{- 144 - 176}{2 ( - 16 )} : 10

The solutions to the quadratic equation are:

t = - 1, t = 10

(\frac{x ^{6}}{9 y ^{- 4}})^{\frac{- 1}{2}}

4 (x + 3) - 7 \geq x + 3 (x + 1)

- 4 x = \frac{11}{5}

\frac{x}{4} + 1 < 1

8 y^{3} + 1

What are the solutions to the equation -16t^2+144t+160=0 ?
The solutions to the equation -16t^2+144t+160=0 are t=-1,t=10
Find the zeros of -16t^2+144t+160=0
The zeros of -16t^2+144t+160=0 are t=-1,t=10